Esme Timbery - Australian Bidjigal shellworker. Article “Esme Timbery” in English Wikipedia has 34.5 points for quality (as of July 1, 2025). The article contains 27 references and 5 sections.
Since the creation of article “Esme Timbery”, its content was written by 20 registered users of English Wikipedia and edited by 20 registered Wikipedia users in all languages.
The article is cited 14 times in English Wikipedia and cited 14 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from July 1, 2025 (including revision history and pageviews for previous years).
| Best Rank | English: #131427 10.2023 |
Global: #234791 10.2023 |
| Best Rank | English: #18129 10.2023 |
Global: #86889 10.2023 |
On 15 February 2026 in multilingual Wikipedia, Internet users most often read articles on the following topics: Jeffrey Epstein, Wuthering Heights, 2026 Winter Olympics, Epstein files, Ilia Malinin, Wuthering Heights, Ghislaine Maxwell, Lucas Pinheiro Braathen, 2026 Winter Olympics medal table, Valentine's Day.
In English Wikipedia the most popular articles on that day were: Jeffrey Epstein, Wuthering Heights, Wuthering Heights (2026 film), 2026 Winter Olympics, Lucas Pinheiro Braathen, Ice hockey at the 2026 Winter Olympics – Men's tournament, Epstein files, John F. Kennedy Jr., Anthony Kim, James Van Der Beek.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from July, 2025. When calculating current popularity and AI of articles data from June 2025 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2025... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(14.68+21.95+0+35.71+100)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
